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How do you solve #12-12n=48#?

Answer 1

Hazel Anglin

#color(purple)"n = - 3"#

#color(magenta)("Subtract 12 on both sides:")#

#cancel12-12n= 48# #cancel-12# #color(white)(aaaa) -12#

12 cancels out on the left side, and when you subtract 12 from 48 on the right you get 36:

#-12n = 36#

#color(greeb)("Divide both sides by -12 to get n by itself.")#

#(cancel"-12"n)/cancel"-12"=(36)/-12#

Now you are just left with #n# on the left side and -3 on the right side.

Therefore, #color(purple)"n = -3"#

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Answer 2

Eva Adamson

To solve the equation 12 - 12n = 48, you first subtract 12 from both sides to isolate the term with the variable:

12 - 12n - 12 = 48 - 12 -12n = 36

Next, divide both sides by -12 to solve for n:

-12n / -12 = 36 / -12 n = -3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.