How do you solve #11\leq 4d + 15#?

Answer 1

#d >= -1#

#11 <= 4d + 15#

We solve inequalities pretty much like normal equations, except that the sign is different and at the end of it may be different with negative numbers.

First, we need to move all the variables on one side of the equation and numbers on the other.

When we move #15# to the left side, then it becomes negative, so as a result: #-4 <= 4d#
Now we divide both sides by 4, and get this: #-1 <= d#
It's usually better to put the variable on the left side when you write an answer, so the answer is #d >= -1#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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