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How do you solve #10x - 7 > 2x + 25#?

Answer 1

Abigail Allen

#x>4#

Let's subtract #2x# from both sides to get

#8x-7>25#

Next, add #7# to both sides to get

#8x>32#

Lastly, we divide both sides by #8# to get

#x>4#

Hope this helps!

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Answer 2

Kennedy Adams

#x > 4#

#10x - 7 > 2x + 25#

Subtract #color(blue)(2x)# from both sides: #10x - 7 quadcolor(blue)(-quad2x) > 2x + 25 quadcolor(blue)(-quad2x)#

#8x - 7 > 25#

Add #color(blue)7# to both sides: #8x - 7 quadcolor(blue)(+quad7) > 25 quadcolor(blue)(+quad7)#

#8x > 32#

Divide both sides by #color(blue)8#: #(8x)/color(blue)8 > 32/color(blue)8#

#x > 4#

This can be said as "#x# is greater than 4."

Hope this helps!

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Answer 3

Eli Assouline

To solve the inequality 10x - 7 > 2x + 25, you need to isolate the variable x.

First, subtract 2x from both sides: 10x - 2x - 7 > 25

This simplifies to: 8x - 7 > 25

Next, add 7 to both sides: 8x > 32

Finally, divide both sides by 8: x > 4

Therefore, the solution to the inequality is x > 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #10x - 7 &gt; 2x + 25#?

How do you solve #10x - 7 > 2x + 25#?