How do you solve #10x + 2 = 7x - 10#?
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To solve the equation 10x + 2 = 7x - 10:
- Subtract 7x from both sides: 10x - 7x + 2 = 7x - 7x - 10
- Simplify: 3x + 2 = -10
- Subtract 2 from both sides: 3x + 2 - 2 = -10 - 2
- Simplify: 3x = -12
- Divide both sides by 3: 3x / 3 = -12 / 3
- Simplify: x = -4
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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