How do you solve #-10+x+4-5=7x-5#?

Question

Genesis Allen · Accepted Answer

First, you gather all the "x" terms on one side of the equation;

and all of the constants on the other side of the equation. You have: #-10 + x + 4 - 5 = 7x - 5# 1st: subtract x from both sides of the equation. (We want to move the x over to the right-hand side, so we do the opposite operation on x. X is positive on the left, so we subtract, and we have to do the same thing to both sides of an equation.): #-10 + x + 4 - 5 = 7x - 5# #.........- x...........- x # You then have: #- 10 + 4 - 5 = 6x - 5# All the x's are now on the right-hand side of the equation. Now combine the constants on the left side of the equation: #- 10 + 4 - 5 = - 15 + 4 = - 11# so we have: #- 11 = 6x - 5# There is one more constant to move, so add it to both sides: We have: #- 11 + 5 = 6x# , which is #- 6 = 6x# Let's write it as: #6x = - 6# Now we need to divide both sides by - 6 in order to end up with only one x: #(6x)/ - 6 = - 6 / - 6#, which equals: #- x = 1# Since we want to know what positive x is, we now multiply both sides of the equation by #- 1# to get: #x = - 1# which is the answer. Now check by plugging #- 1# back into the original equation: #- 10 - 1 + 4 - 5 = 7(- 1) - 5# Do both sides add up to negative 12? They should.

Eva Adamson · Answer

undefined To solve the equation -10 + x + 4 - 5 = 7x - 5, first combine like terms:

-10 + 4 - 5 = -11

So the equation becomes:

x - 11 = 7x - 5

Next, subtract x from both sides:

x - x - 11 = 7x - x - 5

-11 = 6x - 5

Add 5 to both sides:

-11 + 5 = 6x - 5 + 5

-6 = 6x

Divide both sides by 6:

-6 / 6 = 6x / 6

-1 = x

So the solution to the equation is x = -1.