How do you solve #10+a^2=-7a#?
Since we have a second-degree term, we know we are dealing with a quadratic, so we need to set it equal to zero to find its zeroes.
Setting both factors equal to zero, we get
Hope this helps!
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To solve (10 + a^2 = -7a), first, bring all terms to one side to set the equation to zero: (a^2 + 7a + 10 = 0). Then, factor the quadratic equation: ((a + 5)(a + 2) = 0). Finally, solve for (a): (a = -5) or (a = -2).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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