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How do you solve #10/(9z-3)=3/7#?

Answer 1

Savannah Anderson

Cross multiply, then solve for #z#.
#z=79/27#

#10/(9z-3)=3/7#

Multiply by cross.

#10xx7=3(9z-3)#

Simplify.

#70=27z-9#

Add #9# to both sides.

#79=27z#

Divide both sides by #27#.

#79/27=z#

Change positions.

#z=79/27#

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Answer 2

Kennedy Adams

To solve ( \frac{10}{9z - 3} = \frac{3}{7} ), follow these steps:

Cross multiply to eliminate the fractions.
Solve for ( z ) by isolating it on one side of the equation.

Here are the steps in detail:

[ \frac{10}{9z - 3} = \frac{3}{7} ]

Step 1: Cross multiply:

[ 10 \times 7 = 3 \times (9z - 3) ]

Step 2: Solve for ( z ):

[ 70 = 27z - 9 ]

[ 70 + 9 = 27z ]

[ 79 = 27z ]

[ z = \frac{79}{27} ]

So, the solution to the equation is ( z = \frac{79}{27} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.