How do you solve #10+ 4x = 5( x - 6) + 33#?

Answer 1

#x=7#

Take the brackets out:

#10+4x=5x-30+33#

Simplify:

#10+4x=5x+3#

'Doing the same to each side' means rearranging:

#10+4x-4x-3=5x+3-4x-3#

which is equivalent to

#7=x#
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Answer 2

To solve the equation 10 + 4x = 5(x - 6) + 33:

First, distribute the 5 on the right side of the equation:

10 + 4x = 5x - 30 + 33

Combine like terms on the right side:

10 + 4x = 5x + 3

Next, subtract 4x from both sides to isolate the variable term:

10 + 4x - 4x = 5x - 4x + 3

Combine like terms on the left side:

10 = x + 3

Then, subtract 3 from both sides:

10 - 3 = x + 3 - 3

Simplify:

7 = x

So, x = 7.

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Answer 3

To solve the equation (10 + 4x = 5(x - 6) + 33), you first distribute (5) to (x) and (-6) inside the parentheses on the right side of the equation. Then, you combine like terms and solve for (x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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