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How do you solve #10 < –3x + 1#?

Answer 1

#10 < -3x +1#

Add #3x# to both sides #3x+10 < 1# Subtract #10# from both sides #3x<-9# Divide both sides by #3# #x<-3#

Remember that you can perform the following operations on both sides of an inequality without changing the orientation of the inequality: 1. Add or Subtract any value 2. Multiply or Divide by any value #>0#

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Answer 2

Genesis Allen

To solve the inequality 10 < -3x + 1, follow these steps:

Subtract 1 from both sides of the inequality: 10 - 1 < -3x.
Simplify: 9 < -3x.
Divide both sides by -3. Since you're dividing by a negative number, reverse the inequality sign: ( \frac{9}{-3} > x ).
Simplify: -3 > x.

So, the solution is ( x < -3 ).

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Answer 3

Eva Abramson

To solve the inequality (10 < -3x + 1):

First, isolate the variable term by subtracting 1 from both sides:

[ 10 - 1 < -3x ]

[ 9 < -3x ]

Next, divide both sides by -3. Since you're dividing by a negative number, remember to reverse the inequality sign:

[ \frac{9}{-3} > \frac{-3x}{-3} ]

[ -3 > x ]

So, the solution to the inequality is ( x < -3 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #10 &lt; –3x + 1#?

How do you solve #10 < –3x + 1#?