# How do you solve #10 < –3x + 1#?

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To solve the inequality 10 < -3x + 1, follow these steps:

- Subtract 1 from both sides of the inequality: 10 - 1 < -3x.
- Simplify: 9 < -3x.
- Divide both sides by -3. Since you're dividing by a negative number, reverse the inequality sign: ( \frac{9}{-3} > x ).
- Simplify: -3 > x.

So, the solution is ( x < -3 ).

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To solve the inequality (10 < -3x + 1):

- First, isolate the variable term by subtracting 1 from both sides:

[ 10 - 1 < -3x ]

[ 9 < -3x ]

- Next, divide both sides by -3. Since you're dividing by a negative number, remember to reverse the inequality sign:

[ \frac{9}{-3} > \frac{-3x}{-3} ]

[ -3 > x ]

So, the solution to the inequality is ( x < -3 ).

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