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How do you solve #10+3(x+2)=31 #?

Answer 1

Abigail Allen

#x=5#

#10+3(x)+3(2)=31#

#10+3x+6=31#

#16+3x=31#

#3x=31-16#

#3x=15#

#x=#15/3##

#x=5#

ANSWER: #x=5#

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Answer 2

Savannah Anderson

To solve the equation 10 + 3(x + 2) = 31:

Distribute the 3: 10 + 3x + 6 = 31
Combine like terms: 3x + 16 = 31
Subtract 16 from both sides: 3x = 15
Divide both sides by 3: x = 5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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