How do you solve #10 + 2/3t=6#?

Answer 1

#-6#

To isolate #t#, you must first subtract 10 from both sides of the equation: #10+t2/3-10=6-10# #2/3t=-4#
Then, to cancel out the effect of the #2/3# on the #t#, you can multiply both sides by the recipricol of 2/3 which is 3/2
#(2/3*3/2)t=-4*3/2# #t=-12/2# #t=-6#
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Answer 2

To solve the equation 10 + (2/3)t = 6, you would first subtract 10 from both sides to isolate the term involving t. Then, you would multiply both sides by 3/2 to solve for t. The steps would be:

  1. Subtract 10 from both sides: 10 + (2/3)t - 10 = 6 - 10
  2. Simplify: (2/3)t = -4
  3. Multiply both sides by 3/2 to isolate t: (3/2)(2/3)t = -4(3/2)
  4. Simplify: t = -6
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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