How do you solve #10 + 2/3t=6#?
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To solve the equation 10 + (2/3)t = 6, you would first subtract 10 from both sides to isolate the term involving t. Then, you would multiply both sides by 3/2 to solve for t. The steps would be:
- Subtract 10 from both sides: 10 + (2/3)t - 10 = 6 - 10
- Simplify: (2/3)t = -4
- Multiply both sides by 3/2 to isolate t: (3/2)(2/3)t = -4(3/2)
- Simplify: t = -6
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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