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How do you solve # 10+1/3x^2=18#?

Answer 1

Avery Alexander

#x= +-2sqrt(6)#

#10 + 1/3x^2 = 18#

Subtract 10 from both sides

# 1/3x^2 = 8#

Multiply both sides by 3

#x^2 = 24#

Take square root of both sides:

#x = +-sqrt(24) = +-sqrt(4)sqrt(6) = +-2sqrt(6)#

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Answer 2

Eva Adamson

To solve the equation (10 + \frac{1}{3}x^2 = 18), follow these steps:

Subtract 10 from both sides to isolate the fraction term: (\frac{1}{3}x^2 = 8).
Multiply both sides by 3 to get rid of the fraction: (x^2 = 24).
Take the square root of both sides: (x = \pm \sqrt{24}).
Simplify the square root of 24: (x = \pm 2\sqrt{6}).

So, the solutions to the equation are (x = 2\sqrt{6}) and (x = -2\sqrt{6}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.