How do you solve #(1 - y)/(1 + y) = 2/3#?

Answer 1

#y=1/5#

When we have 2 fractions equal to each other then the way to eliminate the fractions is to #color(blue)"cross-multiply"#
#rArra/b=c/drArr ad=bc#

here we obtain

2(1 + y) = 3(1 - y)

multiply out brackets.

hence : 2 + 2y = 3 - 3y

now collect like terms , y to the left and numbers on right. Remember to change the sign of a term when it is moved from one side to the other.

thus : 2y + 3y = 3 - 2 → 5y = 1

divide both sides by 5

#rArr(cancel(5)^1 y)/cancel(5)^1=1/5rArry=1/5#
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Answer 2

To solve the equation (1 - y)/(1 + y) = 2/3:

  1. Cross multiply to eliminate the denominators: (1 - y) * 3 = (1 + y) * 2.
  2. Expand both sides: 3 - 3y = 2 + 2y.
  3. Rearrange terms: 3 - 2 = 2y + 3y.
  4. Simplify: 1 = 5y.
  5. Solve for y: y = 1/5.
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Answer 3

To solve the equation ( \frac{1 - y}{1 + y} = \frac{2}{3} ), we can start by cross-multiplying to eliminate the fractions and then solve for the variable ( y ). Here's the step-by-step process:

[ (1 - y) \cdot 3 = (1 + y) \cdot 2 ]

Expand both sides:

[ 3 - 3y = 2 + 2y ]

Now, combine like terms:

[ -3y - 2y = 2 - 3 ]

[ -5y = -1 ]

Finally, solve for ( y ) by dividing both sides by -5:

[ y = \frac{1}{5} ]

Therefore, the solution to the equation is ( y = \frac{1}{5} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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