# How do you solve #1/(x-6) + 1/(x-2)= 6/5 #?

Solution :

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To solve the equation 1/(x-6) + 1/(x-2) = 6/5, we can start by finding a common denominator for the fractions on the left side. The common denominator is (x-6)(x-2). Multiplying each term by this common denominator, we get (x-2) + (x-6) = (6/5)(x-6)(x-2). Simplifying the equation, we have 2x - 8 = (6/5)(x^2 - 8x + 12). Expanding and rearranging, we obtain 2x - 8 = (6/5)x^2 - (48/5)x + (72/5). Moving all terms to one side, we have (6/5)x^2 - (58/5)x + (152/5) = 0. This is a quadratic equation. We can solve it by factoring, completing the square, or using the quadratic formula.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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