How do you solve #1/(x+3) + 1/(x-3) = 1/(x^2-9)#?
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To solve the equation 1/(x+3) + 1/(x-3) = 1/(x^2-9), we can start by finding a common denominator for the fractions on the left side. The common denominator is (x+3)(x-3). Multiplying each term by this common denominator, we get (x-3) + (x+3) = 1. Simplifying this equation, we have 2x = 1. Dividing both sides by 2, we find x = 1/2. Therefore, the solution to the equation is x = 1/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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