# How do you solve #1/x + 1 = x/2#?

We need to take all the variables ,i.e,x to one side and constants to one side.

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To solve the equation 1/x + 1 = x/2, we can start by multiplying both sides of the equation by 2x to eliminate the denominators. This gives us 2 + 2x = x^2. Rearranging the equation, we have x^2 - 2x - 2 = 0. To solve this quadratic equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), where a = 1, b = -2, and c = -2. Plugging in these values, we get x = (2 ± √(4 + 8)) / 2. Simplifying further, x = (2 ± √12) / 2. This can be simplified as x = 1 ± √3. Therefore, the solutions to the equation are x = 1 + √3 and x = 1 - √3.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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