How do you solve #1/(x1)+3/(x+1)=2#?
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To solve the equation 1/(x1) + 3/(x+1) = 2, you can follow these steps:

Find a common denominator for the fractions on the left side of the equation. In this case, the common denominator is (x1)(x+1).

Multiply each term by the common denominator to eliminate the fractions. This gives you (x+1) + 3(x1) = 2(x1)(x+1).

Simplify the equation by distributing and combining like terms. This results in x + 1 + 3x  3 = 2(x^2  1).

Continue simplifying the equation by combining like terms. This gives you 4x  2 = 2x^2  2.

Rearrange the equation to bring all terms to one side, resulting in 2x^2  4x = 0.

Factor out the common factor of 2x, giving you 2x(x  2) = 0.

Set each factor equal to zero and solve for x. This gives you two possible solutions: x = 0 and x = 2.
Therefore, the solutions to the equation 1/(x1) + 3/(x+1) = 2 are x = 0 and x = 2.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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