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How do you solve #1/x + 1/2x = 1/6 #?

Answer 1

Isaiah Anthony

This equation has no real solutions

#1/x+1/2x=1/6#

First we multiply both sides by #6x# to get rid of the fractions and the unknown in the denominator:

#6+3x^2=x# #3x^2-x+6=0#

Now we look for the solutions of a quadratic equation:

#Delta=(-1)^2-4*3*6=1-72=-71# #Delta<0# so this equation has no real solutions.

So the base equation also has no real solutions.

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Answer 2

Eva Adamson

Is there a formatting problem in the question?

Should it have been:

How do you solve #1/x+1/(2x)=1/6# ?

If so, #x = 9# is the solution.

Assuming the problem is:

How do you solve #1/x+1/(2x)=1/6# ?

Multiply both sides by #6x# to get:

#6+3 = x#

So #x=9#

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Answer 3

Savannah Anderson

Savannah Anderson

To solve the equation 1/x + 1/2x = 1/6, we can start by finding a common denominator for the fractions. The common denominator in this case is 6x. Multiplying each term by 6x, we get 6 + 3 = x. Simplifying further, the equation becomes x = 9. Therefore, the solution to the equation is x = 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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