How do you solve #1/9(2m-16)=1/3(2m+4)#?

Answer 1

m = -7

Multiply both sides by 9. This gives us #9/9 (2m -16) = 9/3(2m + 4)#

which simplifies to

#2m - 16 = 3(2m + 4)#
Simplify the right hand side by multiplying each element by 3 #2m - 16 = 6m + 12#

Add 16 to both sides

#2m - 16 + 16 = 6m + 12 + 16#

which simplifies to

#2m = 6m + 28#

subtract 6m from both sides

#2m - 6m = 6m + 28 - 6m#

which simplifies to

#-4m = 28#

Divide both sides by -4

#((-4)/(-4))m = (28)/(-4)#

which gives us

#m = -7#

Verification Left hand side

#(1/9)((2 * -7) -16)# #(1/9)(-14 -16)# #(1/9)(-30)# #-30/9# #-10/3#
Right Hand Side #(1/3)((2 * -7) + 4))# #(1/3)(-14 + 4)# #(1/3(-10))# #-10/3#

Left side = Right side, proving our answer (m = -7) to be correct.

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Answer 2

To solve the equation 1/9(2m-16)=1/3(2m+4), you can follow these steps:

  1. Multiply both sides of the equation by 9 to eliminate the fraction: 9 * (1/9)(2m-16) = 9 * (1/3)(2m+4)

  2. Simplify: (2m - 16) = 3(2m + 4)

  3. Distribute 3 on the right side: 2m - 16 = 6m + 12

  4. Subtract 2m from both sides: -16 = 4m + 12

  5. Subtract 12 from both sides: -28 = 4m

  6. Divide both sides by 4: m = -7

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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