How do you solve #1 7/16 + s = 9/8#?

Answer 1

#color(red)(s = -5/16)#

#1 7/16 + s = 9/8#

I would multiply both sides of the equation by the lowest common multiple of the denominators.

The lowest common multiple of 16 and 8 is 16.

#16(1 7/16 + s) = 16 × 9/8#
#16×23/16 + 16s = 18#
#23 + 16s = 18#

Subtract 23 from each side,

#23 + 16s -23 = 18-23#
#16s = -5#

Divide both sides by 16.

#(16s)/16 = -5/16#
#s = -5/16#

Check:

#1 7/16 + s = 1 7/16 +(-5/16) = 23/16 -5/16 = 18/16 = 9/8#
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Answer 2

To solve (1 \frac{7}{16} + s = \frac{9}{8}), first convert (1 \frac{7}{16}) to an improper fraction, which is (\frac{23}{16}). Then subtract (\frac{23}{16}) from both sides of the equation. This gives (s = \frac{9}{8} - \frac{23}{16}). Find a common denominator, which is (16). Then compute the difference. (s = \frac{18}{16} - \frac{23}{16} = \frac{-5}{16}). So, (s = -\frac{5}{16}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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