How do you solve #1 7/16 + s = 9/8#?
I would multiply both sides of the equation by the lowest common multiple of the denominators.
The lowest common multiple of 16 and 8 is 16.
Subtract 23 from each side,
Divide both sides by 16.
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To solve (1 \frac{7}{16} + s = \frac{9}{8}), first convert (1 \frac{7}{16}) to an improper fraction, which is (\frac{23}{16}). Then subtract (\frac{23}{16}) from both sides of the equation. This gives (s = \frac{9}{8} - \frac{23}{16}). Find a common denominator, which is (16). Then compute the difference. (s = \frac{18}{16} - \frac{23}{16} = \frac{-5}{16}). So, (s = -\frac{5}{16}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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