How do you solve #1.5x + 0.25 = 1.6x#?

Answer 1

Your final answer is x=1.62788205961

(I will refer to the left side of the equation as A and the right side as B) You need to isolate x by dividing B by x. Then do the opposite to A. Subtract .25 from A and add .25 to B. You should now have #1.5x^2=1.6+0.25#. Then divide A by 1.5 and multiply B by 1.5. You should now have #x^2=2.4+.25#. B should now equal 2.65. Now do the square root of everything: #sqrt(x^2=2.65)#. Your final answer is x=1.62788205961
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Answer 2

To solve the equation (1.5x + 0.25 = 1.6x), you first subtract (1.5x) from both sides to isolate the term with (x). Then, you subtract (0.25) from both sides. Finally, you simplify and solve for (x). The solution is (x = 0.25).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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