How do you solve #(1+53)\div 2#?

Answer 1

#((1+53))/2 = (54)/2 =27#

Use BODMAS (Brackets Orders Division Multiplication Addition And Subtraction. First, add the numbers in the bracket because it's the first, the B, in BODMAS.

#1+53=54#

Then if there's nothing else left in the bracket, move to the outside.

#(54)/2#
Because we only have division left we simply divide #54# by #2#
#54/2=27#

Note: if there were other signs besides division, we'd work them out like this:

#(53+1)/2 + 7 * 4#

would be

Bracket first

#53+1=54#

Then division

#54/2=27#

Then multiplication

#7 * 4=28#

This is what it looks like at this stage

#27+28#

Now simply add the two

#27+28=55#
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Answer 2

To solve (1 + 53) ÷ 2, you first perform the operation inside the parentheses, which is addition, resulting in 54. Then, you divide 54 by 2, which equals 27. Therefore, (1 + 53) ÷ 2 equals 27.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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