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How do you solve #1/4x-5/2=-2#?

Answer 1

Take #4# as common denominator (adapting the numerators to the new one) so you get: #(x-5*2)/(4)=(-2*4)/(4)# now you can cancel the denominators and get: #(x-5*2)/cancel(4)=(-2*4)/cancel(4)# #x-10=-8# #x=10-8# #x=2#

By entering this result back into your original equation, you can verify it. :-)

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Answer 2

Abigail Allen

To solve the equation 1/4x - 5/2 = -2, you would first add 5/2 to both sides to isolate the term with x. This results in 1/4x = -2 + 5/2. Then, simplify the right side of the equation to obtain 1/4x = 1/2. Next, multiply both sides by the reciprocal of 1/4, which is 4/1, to isolate x. This gives x = (1/2) * (4/1), which simplifies to x = 2. Therefore, the solution to the equation is x = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.