How do you solve 1<3x+4<10?
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To solve the inequality (1 < 3x + 4 < 10), we need to isolate (x).
First, subtract 4 from all parts of the inequality:
[ 1 - 4 < 3x + 4 - 4 < 10 - 4 ] [ -3 < 3x < 6 ]
Next, divide by 3:
[ \frac{-3}{3} < \frac{3x}{3} < \frac{6}{3} ] [ -1 < x < 2 ]
So the solution to the inequality (1 < 3x + 4 < 10) is (-1 < x < 2).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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