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How do you solve #|1/3x + 2| - 8 > -3#?

Answer 1

x > 9
x < - 21

#Ix/3 + 2I > -3 + 8 # #Ix/3 + 2I > 5# separate solving into 2 parts: a. #(x/3 + 2) > 5# #x/3 > 3# #x > 9# b. -(x/3 + 2) > 5 -x/3 - 2 > 5 -x/3 > 7 x < - 21 Graph

============ -21------------------- 0---------- 9==============

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Answer 2

Jameson Allen

To solve the inequality |1/3x + 2| - 8 > -3, first, add 8 to both sides to isolate the absolute value term. This gives |1/3x + 2| > 5. Then, split the inequality into two cases: 1/3x + 2 > 5 and 1/3x + 2 < -5. Solve each case separately to find the solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #|1/3x + 2| - 8 &gt; -3#?

How do you solve #|1/3x + 2| - 8 > -3#?