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How do you solve #1/2(x-3)+(3/2-x)=5 x#?

Answer 1

Abigail Allen

#x=0#

Multiply out the brackets giving:

#x/2-3/2+3/2-x=5x#

But #-3/2+3/2=0#

#x/2-x=5x#

Add #x# to both sides

#x/2=5x+x#

#x/2=6x#

Subtract #x/2# from both sides

#0=6x-x/2#

#0=11/2 x#

Thus #x=0#

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Answer 2

Eli Assouline

To solve the equation ( \frac{1}{2}(x-3) + \left(\frac{3}{2}-x\right) = 5x ), follow these steps:

Distribute the fractions and simplify.
Combine like terms to isolate the variable ( x ).
Solve for ( x ) by applying inverse operations.

The solution for ( x ) is ( x = -\frac{1}{4} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.