How do you solve #1/(2(x-3))+3/(2-x)=5 x#?

Answer 1

# x = 1.436#
and
#x = 3.064#

#1/(2(x-3))+3/(2-x)=5 x#

Make the denominators equal:

#1/(2(x-3)) xx(2-x)/(2-x) +3/(2-x) xx (2(x-3))/(2(x-3))=5 x#
#(2-x)/(2(x-3)(2-x)) + (3xx2(x-3))/(2(x-3)(2-x) =5#

Now we can add the numerators:

#=>( (2-x) + 6(x-3))/(2(x-3)(2-x)) =5#
# (2-x +6x-18)/(2(x-3)(2-x)) =5#

Transposition :

# => (2-x +6x-18) = 5xx2(x-3)(2-x)#
#=> 5x -16 = 10(x(2-x) -3(2-x)#
#=> 5x -16 = 10(2x-x^2 -6+ 3x)#
#=> 5x -16 = 10(5x-x^2 -6)#
#=> 5x -16 = 50x-10x^2 -60#
#=> 50x-5x-10x^2 -60+16 = 0#
#=> -10x^2 +45x -44 =0#
#= 10x^2 -45x+ 44 = 0#

Solve using quadratic formula:

#x=( -b +-sqrt(b^2 -4ac))/(2a)#
Here# a= 10, b= -45 and c= 44#
#b^2 -4ac = 2025-1760 = 265#
We get : # x = 1.436# or #x = 3.064#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

To solve the equation 1/(2(x-3))+3/(2-x)=5x, we can follow these steps:

  1. Find a common denominator for the fractions on the left side of the equation. In this case, the common denominator is (2(x-3))(2-x).

  2. Multiply each term by the common denominator to eliminate the fractions.

  3. Simplify the equation by distributing and combining like terms.

  4. Rearrange the equation to isolate the variable x.

  5. Solve for x by applying the appropriate algebraic operations.

The final solution will be the value(s) of x that satisfy the equation.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7