How do you solve #1/2(3x-8)+4 = 2x-(5x+1)#?

Answer 1

#x=-26/9#

#3/2x+4+4=2x-5x-5# distribute #3/2x+8=-3x-5# combine like terms #3x+16=-6x-10# multiply whole equation by 2 to get rid of fraction #9x=-26# #x=-26/9#
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Answer 2

To solve the equation 1/2(3x-8) + 4 = 2x - (5x + 1), follow these steps:

  1. Distribute the 1/2 to (3x - 8) to get 3/2x - 4.
  2. Combine like terms within the parentheses to get 3/2x - 4 + 4 = 2x - (5x + 1).
  3. Simplify to get 3/2x = 2x - 5x - 1.
  4. Combine like terms on the right side to get 3/2x = -3x - 1.
  5. Add 3x to both sides to get (3/2 + 3)x = -1.
  6. Combine the terms on the left side to get (9/2)x = -1.
  7. Multiply both sides by 2/9 to isolate x, giving you x = -2/9.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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