How do you solve #| 1/2-3/4x | + 1=3 #?

Answer 1

#-#2 and 10/3.

The given equation is equivalent to the pair 1/2#-#3 x/4 = #+-#2.
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Answer 2

#x = -2" or "x=10/3" "#Note that #10/3 = 3.33bar3#

The very nature of this type of problem is that it usually has 2 solutions for #x#

We need to end up with the 'Absolute' part of the equation on its own and on the left of the equals sign and everything else on the other.

Given:#" "color(brown)(|1/2-3/4 x|+1=3)#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Simplifying")#

Subtract #color(blue)(1)# from both sides

#" "color(brown)(|1/2-3/4 x|+1color(blue)(-1)" "=" "3color(blue)(-1))#

#" "|1/2-3/4 x|+0" "=" "2#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Solving for "x)#

Think of this as:

#" "|1/2-3/4 x|" "=" "|+-2|#

#color(brown)("Consider: "1/2-3/4 x" "=" "-2" "#

Multiply by (-1 ) giving

#" "-1/2+3/4 x=+2#

#" "3/4 x=2+1/2#

#color(blue)(" " x" "=" "4/3xx5/2" " = " "10/3)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#color(brown)("Consider: "1/2-3/4 x=+2#

Multiply by (-1 ) giving

#" "-1/2+3/4 x=-2#

#" "3/4 x=-2+1/2#

#" "color(blue)(x=4/3xx(-3/2) = -2)#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#" "color(magenta)(x = -2" or "x=10/3)#

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Answer 3

To solve the equation (| \frac{1}{2} - \frac{3}{4}x | + 1 = 3):

  1. Subtract 1 from both sides to isolate the absolute value term: (| \frac{1}{2} - \frac{3}{4}x | = 2).
  2. Since the absolute value of a number can be positive or negative, we set up two equations: a. (\frac{1}{2} - \frac{3}{4}x = 2) b. (\frac{1}{2} - \frac{3}{4}x = -2).
  3. Solve each equation separately for (x).

Solving equation (a):

  1. Subtract (\frac{1}{2}) from both sides: (-\frac{3}{4}x = \frac{3}{2}).
  2. Multiply both sides by (-\frac{4}{3}) to solve for (x): (x = -2).

Solving equation (b):

  1. Subtract (\frac{1}{2}) from both sides: (-\frac{3}{4}x = -\frac{5}{2}).
  2. Multiply both sides by (-\frac{4}{3}) to solve for (x): (x = \frac{10}{3}).

So, the solutions to the equation are (x = -2) and (x = \frac{10}{3}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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