How do you solve #2(t - 6) + 8 + 4(t + 7)=0#?

It is

#2(t - 6) + 8 + 4(t + 7)=0=> 2t-12+8+4t+28=0=> 6t+24=0=>t=-4#

To solve the equation 2(t - 6) + 8 + 4(t + 7) = 0, you would first distribute the numbers outside the parentheses. Then, combine like terms, isolate the variable, and solve for t. Here's the step-by-step process:

1. Distribute the numbers: 2(t - 6) + 8 + 4(t + 7) = 0 2t - 12 + 8 + 4t + 28 = 0

2. Combine like terms: (2t + 4t) + (-12 + 8 + 28) = 0 6t + 24 = 0

3. Move the constant to the other side of the equation: 6t = -24

4. Solve for t: t = -24 / 6 t = -4

To solve the equation 2(t - 6) + 8 + 4(t + 7) = 0, you would first distribute the terms inside the parentheses:

2t - 12 + 8 + 4t + 28 = 0

Combine like terms:

2t + 4t - 12 + 8 + 28 = 0 6t + 24 = 0

Now, isolate the variable term by subtracting 24 from both sides:

6t + 24 - 24 = 0 - 24 6t = -24

Then, divide both sides by 6 to solve for t:

6t / 6 = -24 / 6 t = -4

So, the solution to the equation 2(t - 6) + 8 + 4(t + 7) = 0 is t = -4.