How do you solve #2(t  6) + 8 + 4(t + 7)=0#?
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#2(t  6) + 8 + 4(t + 7)=0=> 2t12+8+4t+28=0=> 6t+24=0=>t=4#
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To solve the equation 2(t  6) + 8 + 4(t + 7) = 0, you would first distribute the numbers outside the parentheses. Then, combine like terms, isolate the variable, and solve for t. Here's the stepbystep process:

Distribute the numbers: 2(t  6) + 8 + 4(t + 7) = 0 2t  12 + 8 + 4t + 28 = 0

Combine like terms: (2t + 4t) + (12 + 8 + 28) = 0 6t + 24 = 0

Move the constant to the other side of the equation: 6t = 24

Solve for t: t = 24 / 6 t = 4
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To solve the equation 2(t  6) + 8 + 4(t + 7) = 0, you would first distribute the terms inside the parentheses:
2t  12 + 8 + 4t + 28 = 0
Combine like terms:
2t + 4t  12 + 8 + 28 = 0 6t + 24 = 0
Now, isolate the variable term by subtracting 24 from both sides:
6t + 24  24 = 0  24 6t = 24
Then, divide both sides by 6 to solve for t:
6t / 6 = 24 / 6 t = 4
So, the solution to the equation 2(t  6) + 8 + 4(t + 7) = 0 is t = 4.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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