How do you solve #0.1d-0.03+0.3d=0.25#?

Answer 1

#d=7/10=0.7#

Yuo can thinking that:

#d=x#

then to find d you have to solve the equation

#0.1x-0.03+0.3x=0.25#

Addiction the terms in x and move the not x terms on the right of =

#0.4x=0.25+0.03#
#0.4x=0.28#

Converting the decimal number in fractions

#4/10x=28/100#

Finding the

#m.c.d. =100#
#(10*4x)/100=28/100#
#(40x)/100=28/100#
#40x=28#
#x=28/40#

Semplyfing fraction by 4

#x=cancel(28)^7/cancel(40)_10=7/10#

Then:

#x=d=7/10#
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Answer 2

To solve the equation 0.1d - 0.03 + 0.3d = 0.25, first combine like terms by adding 0.1d and 0.3d, which gives 0.4d. Rewrite the equation as 0.4d - 0.03 = 0.25. Then, add 0.03 to both sides to isolate the variable term, resulting in 0.4d = 0.28. Finally, divide both sides by 0.4 to solve for d, giving d = 0.7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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