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How do you sketch the graph of #y=-1/4x^2# and describe the transformation?

Answer 1

This is an equation of parabola.
Standard equation of a parabola with Y axis symmetry is given by
#(X-h)^2 = 4p(Y-k)#

Simply rearranging the terms from y= #-1/4 x^2# you can get the standard equation of a parabola as #4*(-1)(Y-k) = (x-0)^2#. This is a downward opening parabola with negative Y axis as the axis of symmetry. From the standard equation the co-ordinates of focus are (h,k+p). So the focus of this parabola is (0,-1). the vertex is (h,k) => vertex is (0,0)

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Answer 2

Kennedy Adams

To sketch the graph of (y = -\frac{1}{4}x^2), start with the basic parabolic graph of (y = x^2), then reflect it in the x-axis, and finally stretch it vertically by a factor of 1/4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.