How do you simplify #(y^2+8y-9)/(y^2-5y+4)#?

Question

Abigail Allen · Accepted Answer

=#((y+9))/((y-4))#

Because there are + and - signs in the numerator and denominator, which indicate that there are terms rather than factors, even though we have a fraction, we MAY NOT CANCEL.

First, factor the denominator and numerator.

#((y+9)(y-1))/((y-4)(y-1)) " now we have factors"#

#((y+9)cancel(y-1))/((y-4)cancel(y-1))#

=#((y+9))/((y-4))#

Jameson Allen · Answer

undefined To simplify the expression (y^2+8y-9)/(y^2-5y+4), you can factor both the numerator and the denominator. The numerator can be factored as (y+9)(y-1), and the denominator can be factored as (y-4)(y-1).

Next, you can cancel out the common factor of (y-1) in both the numerator and the denominator.

After canceling out the common factor, the simplified expression becomes (y+9)/(y-4).

Eva Adamson · Answer

undefined To simplify the expression (y^2 + 8y - 9) / (y^2 - 5y + 4), first factor both the numerator and the denominator.

The numerator factors as (y + 9)(y - 1), and the denominator factors as (y - 4)(y - 1).

Now, cancel out the common factors:

(y + 9)(y - 1) / ((y - 4)(y - 1))

Now, simplify the expression by canceling out the common factor (y - 1) from the numerator and the denominator:

(y + 9) / (y - 4)

So, the simplified form of the expression is (y + 9) / (y - 4).