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How do you simplify # (y^2 -2y -15)/ (2y^2 -50)#?

Answer 1

Ethan Adkins

#(y+3)/(2y+10)#

#(y^2-2y-15)/(2y^2-50)#

=#((y-5)(y+3))/(2(y^2-25))#

=#((y-5)(y+3))/(2(y+5)(y-5))#

=#(y+3)/(2(y+5))#

=#(y+3)/(2y+10)#

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Answer 2

Hazel Anglin

To simplify the expression (y^2 - 2y - 15) / (2y^2 - 50), we can factor both the numerator and the denominator.

The numerator can be factored as (y - 5)(y + 3), and the denominator can be factored as 2(y - 5)(y + 5).

Now, we can cancel out the common factor of (y - 5) from both the numerator and the denominator.

This leaves us with (y + 3) / (2y + 10).

Finally, we can simplify further by dividing both the numerator and the denominator by 2, resulting in (y + 3) / (y + 5).

Therefore, the simplified form of (y^2 - 2y - 15) / (2y^2 - 50) is (y + 3) / (y + 5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.