How do you simplify #(x + y)(x - y)#?

Answer 1

#(x+y)(x-y)=x^2-y^2#

To simplify #(x+y)(x-y)# we use distributive property of number systems.
Let us treat #(x+y)# as a single number and distribute it over #(x-y)#.
This makes #(x+y)(x-y)#
= #(x+y)x-(x+y)y#

Now using commutative property of multiplication the above is equivalent to

#x(x+y)-y(x+y)# and now again using distributive property this is equivalent to
#x xx x+x xx y- y xx x-yxxy#
#x xx x+x xx y- x xx y-yxxy#
= #x^2+xy-xy-y^2#
= #x^2+cancel(xy)-cancel(xy)-y^2#
= #x^2-y^2#
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Answer 2

To simplify ( (x + y)(x - y) ), you can use the distributive property, which states that ( (a + b)(c + d) = ac + ad + bc + bd ). Applying this property, you get ( x^2 - xy + xy - y^2 ). Simplifying further, ( x^2 - y^2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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