How do you simplify #((x)/(x+1))/(x+x/3)#?

Answer 1

#3/(4x+4)#

#(x/(x+1))/(x+x/3)#

First, add the terms in the denominator.

#=(x/(x+1))/((3x)/3+x/3)# (create a common denominator)
#=(x/(x+1))/((4x)/3)# (combine into a single fraction)
#=cancel(x)/(x+1)*3/(4cancel(x))# (rewrite expression and cancel)
#=3/(4(x+1))# (multiply fractions)
#=3/(4x+4)# (distribute in the denominator)
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Answer 2

#3/(4x+4)#

Given:#" "(x/(x+1))/(x+x/3)#
Multiply by 1 but in the form of #3/3# giving:
#(x/(x+1))/(x+x/3)xx3/3" "=" "((3x)/(x+1))/(3x+x)" "=" "((3x)/(x+1))/(4x)#

This is the same as:

#(3x)/(x+1)xx1/(4x)" "=" "x/x xx3/4xx1/(x+1)" "=" "3/(4x+4)# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #color(blue)("Check")#
Set #x=1#
#(x/(x+1))/(x+x/3)" "->" "1/2xx1/((4/3))" "=" "3/8#
#3/(4x+4)" "->" "3/8#

They match!

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Answer 3

#frac(3 x)(4 (x^(2) + x))#

#= 3/(4(x+1)#

We have: #frac(frac(x)(x + 1))(x + frac(x)(3))#
#= frac(x)(x + 1) times frac(1)(x + frac(x)(3))#
#= frac(x)((x + 1)(x + frac(x)(3)))#
#= frac(x)((x)(x) + (x)(frac(x)(3)) + (1)(x) + (1)(frac(x)(3))#
#= frac(x)(x^(2) + frac(x^(2))(3) + x + frac(x)(3))#
#= frac(x)(x^(2) (1 + frac(1)(3)) + x (1 + frac(1)(3)))#
#= frac(x)(frac(4)(3) x^(2) + frac(4)(3) x)#
#= frac(x)(frac(4)(3) (x^(2) + x))#
#= frac(3 x)(4 (x^(2) + x))" "larr# factorise
#=frac(3 x)(4x (x + 1))#
#= 3/(4(x+1)#
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Answer 4

To simplify ((x)/(x+1))/(x+x/3), we can follow these steps:

  1. Simplify the expression within the parentheses: (x)/(x+1) becomes x/(x+1).
  2. Simplify the expression x+x/3: To add x and x/3, we need a common denominator, which is 3. So, x+x/3 becomes (3x+x)/3, which simplifies to (4x)/3.

Now, we can rewrite the expression as x/(x+1) divided by (4x)/3.

To divide by a fraction, we multiply by its reciprocal. Therefore, we can rewrite the expression as x/(x+1) multiplied by 3/(4x).

Now, we can simplify further by canceling out common factors. The x in the numerator and denominator cancels out, leaving us with 1/(x+1) multiplied by 3/4.

So, the simplified expression is (3/4)/(x+1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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