How do you simplify #(x + 9)(x - 2)(x - 7)#?

Answer 1

#x^3-67x+126#

#"factors of the form"#
#(x+a)(x+b)(x+c)" may be expanded as"#
#x^3+(a+b+c)x^2+(ab+bc+ac)x+abc#
#"here " a=9,b=-2" and " c=-7#
#rArr(x+9)(x-2)(x-7)#
#=x^3+(9-2-7)x^2+(-18+14-63)x+(9xx-2xx-7)#
#=x^3-67x+126#
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Answer 2

To simplify (x + 9)(x - 2)(x - 7), you can use the distributive property and multiply each pair of binomials together. Then, you can combine like terms and simplify the expression further. The simplified expression is (x^3 - 10x^2 - 61x + 126).

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Answer 3

To simplify the expression (x + 9)(x - 2)(x - 7), you can use the distributive property and multiply the terms together:

(x + 9)(x - 2)(x - 7) = (x^2 - 2x + 9x - 18)(x - 7) = (x^2 + 7x - 18)(x - 7) = x^3 - 7x^2 - 18x + 49x - 126 = x^3 - 7x^2 + 31x - 126

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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