How do you simplify #(x-6)/(x^2-7x+6)#?

Answer 1

#1/(x-1)#

This equation can be separated into two parts, the top and the bottom, which we can simplify further.

The top is already simplified as far as possible (for now) so let's jump to the bottom instead:

#x^2 - 7x + 6# This can be factored into the following: #(x-6)(x-1)# -6 and -1 both add to equal -7, and multiplied they equal 6, fitting the polynomial.
From here we can cancel an #(x-6)# from the top and bottom:
#(x-6)/((x-6)(x-1))# #cancel(x-6)/(cancel(x-6)(x-1))# #1/(x-1)#

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Answer 2

To simplify the expression (x-6)/(x^2-7x+6), you can factor the denominator and cancel out any common factors with the numerator. The denominator can be factored as (x-1)(x-6). Therefore, the simplified expression is (x-6)/(x-1)(x-6). Since (x-6) appears in both the numerator and denominator, it can be canceled out, resulting in the simplified expression of 1/(x-1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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