How do you simplify #(x+5 )/ (x^2-25)#?
Hope this helps!
By signing up, you agree to our Terms of Service and Privacy Policy
By signing up, you agree to our Terms of Service and Privacy Policy
To simplify (x+5)/(x^2-25), we can factor the denominator as (x+5)(x-5). Then, we can cancel out the common factor of (x+5) in the numerator and denominator. The simplified form is 1/(x-5).
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you solve #\frac { 3} { 4} b + 5= 14#?
- How do you simplify #(x-3)/(2x-8)*(6x^2-96)/(x^2-9)#?
- How do you subtract #\frac { 3a + 5} { a - 4} - \frac { 6a + 7} { a - 4}#?
- If y varies jointly as x and z and inversely as w, and y = 3/2 when x=2, z=2, and w=4. How do you find the equation of variation for the given situation?
- Is #y=x/10# a direct of inverse variation?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7