# How do you simplify #(x-5)/(x^2-25)#?

Divide the denominator by the square difference.

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To simplify (x-5)/(x^2-25), we can factor the denominator as the difference of squares: (x^2-25) = (x-5)(x+5). Therefore, the expression simplifies to 1/(x+5).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you simplify #(6y)/(y^2+y-72) div y^6/(8-y)#?
- How do you simplify #(8a^2-6a-9)/( 6a^2-5a-6) ÷ (4a^2+11a+6)/( 9a^2+12a+4)#?
- Suppose z varies directly with x and inversely with the square of y. If z=18 when x=6 and y=2, what is z when x=8 and y=9?
- How do you solve #(x^2-3)/(x+2)=(x-3)/2#?
- Suppose y varies inversely as x and y=24 when x= 3, how do you find x when y = 36?

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