How do you simplify #(x^2+8x+16)/(x+2)div(x^2+6x+8)/(x^2-4)#?

Answer 1

#((x+4)(x-2))/((x+2))#

#(x^2+8x+16)/(x+2)div(x^2+6x+8)/(x^2-4)#

To divide by a fraction, multiply by the reciprocal:

#color(blue)((x^2+8x+16))/(x+2)xx(color(red)(x^2-4))/color(green)((x^2+6x+8))#

You cannot cancel with fractions unless there are factors.

Factorise wherever possible:

#color(blue)((x+4)(x+4))/(x+2) xx color(red)((x+2)(x-2))/color(green)((x+4)(x+2))#

Cancel common factors

#color(blue)(cancel((x+4))(x+4))/cancel((x+2)) xx color(red)(cancel((x+2))(x-2))/color(green)(cancel((x+4))(x+2))#
#=((x+4)(x-2))/((x+2))#
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Answer 2

The factored expression is #(x^2+2x-8)/(x+2)#.

Here's the strategy:

First, factor all the polynomials. Then, cancel any common terms. Next, change the division of two fractions to multiplication, and flip the second fraction. Lastly, multiply the fractions and cancel any factors in common.

#color(white)=(x^2+8x+16)/(x+2)div(x^2+6x+8)/(x^2-4)#
#=((x+4)(x+4))/(x+2)div((x+2)(x+4))/((x-2)(x+2))#
#=((x+4)^2)/(x+2)div(color(red)cancelcolor(black)((x+2))(x+4))/((x-2)color(red)cancelcolor(black)((x+2)))#
#=((x+4)^2)/(x+2)div(x+4)/(x-2)#
#=((x+4)^2)/(x+2)xx(x-2)/(x+4)#
#=((x+4)^color(red)cancelcolor(black)2(x-2))/((x+2)color(red)cancelcolor(black)((x+4)))#
#=((x+4)(x-2))/(x+2)#
#=(x^2+2x-8)/(x+2)#

Here's what the graph looks like:

graph{(x^2+2x-8)/(x+2) [-30.54, 30.53, -28.27, 28.27]}

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Answer 3

To simplify the expression, we can start by factoring the numerator and denominator separately.

The numerator (x^2 + 8x + 16) can be factored as (x + 4)(x + 4), or (x + 4)^2.

The denominator (x + 2) can be factored as (x + 2).

The second fraction's numerator (x^2 + 6x + 8) can be factored as (x + 2)(x + 4).

The second fraction's denominator (x^2 - 4) can be factored as (x + 2)(x - 2).

Now, we can rewrite the expression as (x + 4)^2 / (x + 2) * (x + 2)(x - 2) / (x + 2).

Next, we can cancel out the common factors in the numerator and denominator.

(x + 4)^2 / (x + 2) * (x - 2) / 1.

Finally, we simplify further by multiplying the remaining terms.

(x + 4)^2 * (x - 2) / (x + 2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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