# How do you simplify #(x^2+4x-32)/(x+8)# and what are the ecluded values fot he variables?

Let's begin by factorising the numerator using the "middle-term break":

The denominator of a fraction can never equal to zero.

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To simplify the expression (x^2+4x-32)/(x+8), we can factor the numerator and then cancel out any common factors with the denominator. The numerator can be factored as (x+8)(x-4). Therefore, the simplified expression is (x-4).

The excluded values for the variable x are the values that make the denominator equal to zero, since division by zero is undefined. In this case, the excluded value is x = -8, as it would make the denominator (x+8) equal to zero.

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