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How do you simplify #(x^2 - 3x)/(2x - 6)#?

Answer 1

#x/2#

To simplify algebraic fractions you need to factorise the top and bottom as much as you can and then see what terms can be cancelled.

At the top, we can take out a factor of #x# and at the bottom, we can take out a factor of #2#.

#(x^2-3x)/(2x-6)#

#=(x(x-3))/(2(x-3))#

We can now cancel the #x-3# from the top and bottom.

#=(xcancel((x-3)))/(2cancel((x-3)))#

#=x/2#

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Answer 2

Hazel Anglin

#x/2#

Some times they are easier to spot than other times. The trick is to look for things that can be cancelled. You get better at this the more practice you do.

#(xcancel((x-3)))/(2cancel((x-3))) = x/2#

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Answer 3

Jace Anderson

To simplify the expression (x^2 - 3x)/(2x - 6), we can factor out an x from the numerator and a 2 from the denominator. This gives us x(x - 3)/(2(x - 3)). The (x - 3) terms cancel out, leaving us with x/2 as the simplified expression.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.