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How do you simplify #(x^2+3x+2)/(x^2-1)#?

Answer 1

Ethan Adkins

#(x²+3x+2)/(x²-1)=(x+2)/(x-1)#

#(x²+3x+2)/(x²-1)# #=(cancel((x+1)) (x+2))/((x-1)cancel((x+1)))# #=(x+2)/(x-1)# \0/ here's our answer!

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Answer 2

Julia Adams

First we should split the middle term

By the video... you should have understood that we need to make #3x# in two number that one is divisible by 2 and the other is divisible itself

#(x^2+x+2x+2)/(x^2-1)#

You should always remember that
#1=1^2#
It'll always help you

Factorize
#(x(x+1)+2(x+1))/(x^2-1^2)#

It is a law of exponents
#a^2-b^2=(a+b)(a-b)#

#((x+2)cancel((x+1)))/((x-1)cancel((x+1)))#

You are left with
#(x+2)/(x-1)#

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Answer 3

Savannah Anderson

To simplify the expression (x^2+3x+2)/(x^2-1), you can factor both the numerator and the denominator. The numerator can be factored as (x+1)(x+2), and the denominator can be factored as (x+1)(x-1).

Next, you can cancel out the common factor of (x+1) in both the numerator and the denominator.

After canceling out the common factor, the simplified expression becomes (x+2)/(x-1).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.