How do you simplify the expression #(sqrt2+sqrt3)^2#?

Answer 1

Nathan Axel

You work out the expression #(a+b)^2=a^2+2ab+b^2#

#=sqrt2^2+2*sqrt2*sqrt3+sqrt3^2#

#=2+2*sqrt(2*3)+3#

#=5+2sqrt6#

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Answer 2

Isaiah Anthony

To simplify the expression (sqrt2+sqrt3)^2, you can use the FOIL method. First, square the first term, which is sqrt2, to get 2. Then, multiply the first term, sqrt2, by the second term, sqrt3, to get sqrt6. Multiply the second term, sqrt3, by the first term, sqrt2, to get sqrt6 again. Finally, square the second term, sqrt3, to get 3. Combine the like terms, 2 and 3, to get 5. Therefore, (sqrt2+sqrt3)^2 simplifies to 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.