How do you simplify #sqrt72 * sqrt32#?

Answer 1

The answer is #48#

To multiply square roots, it is easiest to just multiply the radicands (the numbers under the radical sign) and imagine the radical signs away for a minute. So when we see: #sqrt75 xx sqrt32# mentally remove the radicands and multiply. #72 xx 32 = 2,304#
Now, we're going to put the radical sign back on and find the square root: #sqrt2304 = 48#
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Answer 2

# 48#

#sqrt72xxsqrt32#
#sqrt72=sqrt(2xx2xx2xx3xx3)#
#sqrt32=sqrt(2xx2xx2xx2xx2)#

Consequently,

#sqrt72xxsqrt32=sqrt(2xx2xx2xx3xx3)xxsqrt(2xx2xx2xx2xx2)#
#= 2xx3xxsqrt2xx2xx2xxsqrt2#
#= 2xx3xx2xx2xx2#
#= 48#

I hope this is helpful.

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Answer 3

To simplify sqrt(72) * sqrt(32), you can multiply the numbers under the square roots together:

sqrt(72) * sqrt(32) = sqrt(72 * 32) = sqrt(2304)

Now, find the square root of 2304:

sqrt(2304) = 48

Therefore, sqrt(72) * sqrt(32) simplifies to 48.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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