How do you simplify #(sqrt7+5)(sqrt7-5)#?

Answer 1

See the entire simplification process below:

To multiply and simplify these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(sqrt(7)) + color(red)(5))(color(blue)(sqrt(7)) - color(blue)(5))# becomes:
#(color(red)sqrt(7) xx color(blue)(sqrt(7))) - (color(red)(sqrt(7)) xx color(blue)(5)) + (color(red)(5) xx color(blue)(sqrt(7))) - (color(red)(5) xx color(blue)(5))#
#sqrt(7)^2 - 5sqrt(7) + 5sqrt(7) - 25#

We can now combine like terms:

#7 + (-5 + 5)sqrt(7) - 25#
#7 + 0 - 25#
#-18#
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Answer 2

To simplify the expression (sqrt7+5)(sqrt7-5), we can use the difference of squares formula. The formula states that (a+b)(a-b) is equal to a^2 - b^2. Applying this formula to the given expression, we have (sqrt7)^2 - 5^2, which simplifies to 7 - 25, resulting in -18. Therefore, the simplified form of (sqrt7+5)(sqrt7-5) is -18.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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