How do you simplify #sqrt50 + sqrt63 - sqrt32#?

May God bless you all. I hope this explanation helps.

To simplify the expression sqrt50 + sqrt63 - sqrt32, we can break down the square roots into their simplest forms and then combine like terms.

sqrt50 simplifies to 5√2, sqrt63 simplifies to 3√7, and sqrt32 simplifies to 4√2.

Therefore, the expression simplifies to 5√2 + 3√7 - 4√2.

Since 5√2 and -4√2 are like terms, they can be combined to give √2.

Thus, the simplified expression is √2 + 3√7.

To simplify ( \sqrt{50} + \sqrt{63} - \sqrt{32} ), first, break down each square root into its prime factors. Then, identify any perfect squares that can be pulled out. Finally, combine like terms.

( \sqrt{50} = \sqrt{2 \times 25} = 5\sqrt{2} )

( \sqrt{63} = \sqrt{9 \times 7} = 3\sqrt{7} )

( \sqrt{32} = \sqrt{16 \times 2} = 4\sqrt{2} )

Now, substitute these values back into the original expression:

( 5\sqrt{2} + 3\sqrt{7} - 4\sqrt{2} )

Combine like terms:

( (5\sqrt{2} - 4\sqrt{2}) + 3\sqrt{7} )

( (5 - 4)\sqrt{2} + 3\sqrt{7} )

( \sqrt{2} + 3\sqrt{7} )

So, ( \sqrt{50} + \sqrt{63} - \sqrt{32} ) simplifies to ( \sqrt{2} + 3\sqrt{7} ).