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How do you simplify #sqrt20 + sqrt64 - sqrt125#?

Answer 1

Isaiah Anthony

#8+2sqrt3-5sqrt5=15.716#

#sqrt20+sqrt64-sqrt125#

= #sqrt(2xx2xx5)+sqrt(2xx2xx2xx2xx2xx2)-sqrt(5xx5xx5)#

= #2sqrt3+(2xx2xx2)-5sqrt5#

= #8+2sqrt3-5sqrt5#

= #8+3.464-11.18=15.716#

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Answer 2

Abigail Allen

To simplify sqrt20 + sqrt64 - sqrt125, we can simplify each square root individually and then combine like terms.

sqrt20 simplifies to 2sqrt5, as 20 can be factored into 2 * 2 * 5, and we take out the square root of 2 * 2, which is 2, and leave the square root of 5 as it is.

sqrt64 simplifies to 8, as 64 is a perfect square.

sqrt125 simplifies to 5sqrt5, as 125 can be factored into 5 * 5 * 5, and we take out the square root of 5 * 5, which is 5, and leave the square root of 5 as it is.

Therefore, the simplified expression becomes 2sqrt5 + 8 - 5sqrt5.

Combining like terms, we have -3sqrt5 + 8 as the final simplified expression.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.