How do you simplify #sqrt2/sqrt6#?

Answer 1

Rationalize the denominator to get #sqrt3/3#

Start by multiplying the fraction by #sqrt6/sqrt6#,
#(sqrt6xxsqrt2)/(sqrt6xxsqrt6" "# Simplify to get
#sqrt12/6#
#=(sqrt4 xx sqrt3)/6" "# Finally, work out #sqrt4# in the numerator:
#=(2sqrt3)/6 = sqrt3/3#
Remember that #sqrtx/sqrty=sqrt(xy)/y#
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Answer 2

To simplify sqrt2/sqrt6, we can rationalize the denominator by multiplying both the numerator and denominator by sqrt6. This gives us sqrt2 * sqrt6 / sqrt6 * sqrt6. Simplifying further, we have sqrt(2 * 6) / 6, which simplifies to sqrt12 / 6. Finally, we can simplify sqrt12 to 2sqrt3, so the simplified form of sqrt2/sqrt6 is 2sqrt3/6.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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